Question about the fundamental group of simplicial complex.

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Suppose we have a simplicial complex G that is finite connected.
(1)The fundamental group of G is finite;
(2)The universal cover of G is compact.
Question:
Can (1) implies (2)?
Thanks.

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Yes. In the universal cover $p\colon\tilde G\to G$, we have that $p^{-1}(x)$ always has $|\pi_1(G)|$ elements. If you have an open cover of $\tilde G$, project it down to $G$ and take a finite subcover. Then to get an open subcover of $\tilde G$, you will need at most $|\pi_1(G)|$ sets for every set in the finite subcover of $G$.