Suppose that x and y are real numbers such that log3(x + y4) = log3(x − y) + log3(x + y), and 10 = log3(x − 2y) + log3(x + 2y). Find the last two digits of x.
I got x + y4=x2 - y2 and 310 = x2 -4y4 using basic properties of logarithm but can't do anything afterwards