I have a little question on integral and irrationality :
Imagine you have: $$\int_{a}^{b}f(x)dx=p$$
Where $p$ is irrational
Can we deduce that there is $b\leq \varepsilon \leq a$ such that $f(\varepsilon)$ is irrational ?
Thanks a lot for your time
I have a little question on integral and irrationality :
Imagine you have: $$\int_{a}^{b}f(x)dx=p$$
Where $p$ is irrational
Can we deduce that there is $b\leq \varepsilon \leq a$ such that $f(\varepsilon)$ is irrational ?
Thanks a lot for your time
No. Let $a=0, b=\sqrt 2, f(x)=1$.