Question involving integration and irrationality

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I have a little question on integral and irrationality :

Imagine you have: $$\int_{a}^{b}f(x)dx=p$$

Where $p$ is irrational

Can we deduce that there is $b\leq \varepsilon \leq a$ such that $f(\varepsilon)$ is irrational ?

Thanks a lot for your time

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No. Let $a=0, b=\sqrt 2, f(x)=1$.

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Hint: take $b - a$ irrational, $f =$ some constant...