A really simple question, but I thought I'd ask anyway. Does $n<x^n<(n+1)$ imply $\sqrt[n] n < x < \sqrt[n] {n+1}$?
Thank you very much.
A really simple question, but I thought I'd ask anyway. Does $n<x^n<(n+1)$ imply $\sqrt[n] n < x < \sqrt[n] {n+1}$?
Thank you very much.
Not in general, but yes if $x\geq 0$.
Otherwise, take $$ 2 < x^2 < 3 $$ with $x = \frac{3}{2}$.