Question on quadratic equations .

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A quadratic equation with roots $m$ and $n$ where $mn=4$ satisfies the equation $\frac {m}{m-1} + \frac {n}{n-1}=\frac {a^2 -7}{a^2 -4}$ . We have to find the number of integral values of $a$ for $m$, $n \in (1,4)$.

By comparing the given I found the quadratic equation as $x^2 -(a^2 +1)x +4 =0$.

But now after that I am stuck

Can anybody help me out how to proceed?

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Hint:

The condition for the roots to lie within $(a,b)$ [i.e. $(1,4)$] should be used.

$f(a)>0$, $f(b)>0$, $x$ coordinate of vertex between $a$ and $b$ , $D \geq 0$ (discriminant)