I was trying to solve he following two questions from a competitive exam paper. Both the questions are linked with following statement.
Let $f_n(x)=\frac{x}{\{(n-1)x+1\}\{nx+1\}}$ and $s_n(x)=\displaystyle \sum_{j=1}^nf_j(x)\forall x\in[0,1]$
First Question:
The sequence $\{s_n\}$
- converges uniformly on $[0,1]$
- converges pointwise on $[0,1]$ but not uniformly
- converges pointwise for $x=0$ but not for $x\in(0,1]$
- doesnot converge for $x\in [0,1]$
Second Question:
$\displaystyle\lim_{n\to \infty}\int_0^1s_n(x)dx=1$ is obtained by
- dominated convergence theorem
- Fatou's Lemma
- the fact that $\{s_n\}$ converges uniformly on $[0,1]$
- the fact that $\{s_n\}$ converges pointwise on $[0,1]$
What I have done so far for the first question is that $f_n(x)=\frac{1}{\{(n-1)x+1\}}-\frac{1}{\{nx+1\}}$ which shows for a fixed $x$ $f_n(x)\rightarrow 0$ as $n\rightarrow \infty$ So I think pointwise convergence can be assured. But can I claim the pointwise convergence of $\{s_n\}$ from here?I am not sure about this.Also I have no idea about the uniform convergence.
and for the second question I am completely stuck.I only know the statements of the two theorems given in the options. Please help.
I admit that I don't have a great concept about convergence of sequence and series of functions and apologise for not showing much effort from my end.
Any help will be very helpful.Thnx in advance.
The decomposition
$$f_n(x) = \frac{1}{(n-1)x+1} - \frac{1}{nx+1}$$
shows that the sum telescopes,
$$s_n(x) = 1 - \frac{1}{nx+1}.\tag{1}$$
From that it is pretty easy to see how $(s_n)$ converges and to what. (Note: uniform convergence would imply continuity of the limit.)
$(1)$ shows that $(s_n)$ is uniformly bounded, so the dominated convergence theorem is one way to obtain the integral.