Question Regarding Logs specifically logs with $x$s involved

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$$\log(5x + 5) = 2\log(x + 1)$$

Thats the original question. So far I have gotten.

$$\log(5x + 5) = \log(x + 1)^2$$

I am not looking for the answer maybe just a hint in the right direction.

Thanks!

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Hint:

A logarithm is an injective function, which means that if $\log(a)=\log(b)$, then $a=b$.

Just be careful, that $\log(a)=\log(b)$ also implicitly means that $a,b>0$.