$$\log(5x + 5) = 2\log(x + 1)$$
Thats the original question. So far I have gotten.
$$\log(5x + 5) = \log(x + 1)^2$$
I am not looking for the answer maybe just a hint in the right direction.
Thanks!
$$\log(5x + 5) = 2\log(x + 1)$$
Thats the original question. So far I have gotten.
$$\log(5x + 5) = \log(x + 1)^2$$
I am not looking for the answer maybe just a hint in the right direction.
Thanks!
Hint:
A logarithm is an injective function, which means that if $\log(a)=\log(b)$, then $a=b$.
Just be careful, that $\log(a)=\log(b)$ also implicitly means that $a,b>0$.