So, I was studying for a test and I came across this problem:
Sorry for the disorganized format, but it seemed like a lot of info to throw into text. I'm a bit confused on how I'd go about finding the answer here, I understand how to integrate and derive, but I'm a bit lost on how I'd go about accomplishing this problem.
Let $u=x^2-1$ then $du=2xdx$. Evaluating u on the limit points the integral becomes $$ \frac{1}{2}\int_3^8 f'(u)du. $$ What can you say now using the graph given?