Radical of ideal

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My question is pretty easy, however I got stuck to get the answer.

Assume the polynomial ring $ R=\mathbb Z[x,y]$ and $I=(xy)$ be an ideal of $R$. I want to compute the radical of $I$.

I am trying to show that $I$ is prime ideal since I know tha radical for prime ideal will be the prime ideal itself. Anyway, what is the radical of $I$.

Any help will be appreciated.

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If $P\in Rad(I)$ then there exists $k\in\mathbb{N}$ and $Q\in\mathbb{Z}[x,y]$ such that $P^k=xyQ$. And obviously, $k>0$.

Consequently, $x$ and $y$ divide $P^k$.

But $x$ and $y$ are irreducible. Hence, by Euclid's lemma, each of them must divide $P$.

Finally, since $x$ and $y$ are coprime, their lcm (namely $xy$) must divide $P$. So $P\in I$.

Hoping it's correct ...