What can be said about the rank of a diagonalizable matrix?
2026-03-28 10:03:49.1774692229
Rank of a diagonalizable matrix?
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Let $e_i$ be the $n \times 1$ vector with a $1$ in the $i$-th component and $0$'s everywhere else.
For any $0 \le k \le n$, the $n \times n$ matrix $A = \displaystyle\sum_{i = 1}^{k}e_ie_i^T$ is diagonalizable has rank $k$.
Hence, a matrix being diagonalizable tells you nothing about its rank.