Rational Logarithms

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My question is about when a logarithm is rational
for example $$\log _4 32=5/2$$ and it is rational,

but $$\log _433=2.5221970596792267...$$
is not.

What should be the relation between a and b in order the logarithm below to be rational?

$$\log _ab$$

2

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0
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That's a funny question to me.

Just observe if $\log _{a}b$ is rational then there must exist integers $p,q$ with $q\ne0$ and $gcd(p,q)=1$ such that, $$\log_ab=\frac{p}{q}\\\implies b=a^{\frac{p}{q}}\\ \implies b^q-a^p=0$$

So the relation between $a,b$ is that $b^q=a^p$ for some $q\ne 0,p$ integers and $\gcd(p,q)=1$.

0
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If both $a$ and $b$ can be expressed as a power of the same number, so $a=c^{\alpha}$ and $b=c^{\beta}$ then \begin{eqnarray*} \log_a(b) = \frac{\beta}{\alpha}. \end{eqnarray*}