I have the following equation that is used in target strength-length relationships in fish.
Equation:
$TS= 20log_{10}(L) + b_{20}$
I have values for $TS$ and $b_{20}$ aad trying to solve for $log_{10}(L)$. I rearranged the equation but am unsure I did it properly and am getting weird answers. Here is the resulting equation:
$L= 10^\frac{(TS + b_{20})}{20}$
Is this correct? I found a resource online that said I had to multiply the value by 10 before I did this but that doesn't make sense to me. Also, the $TS$ values are in log form in the rearranged equation, should they be converted to linear before going in? Or is the rearranged equation already accounting for that? Thank you in advance.