How do we get Wallis Formula $$\frac{\pi}{2}=\lim_{l\to\infty} \prod_{j=1}^{l+1}\frac{(2j)(2j)}{(2j-1)(2j-1)} $$
from $$\lim_{n\to\infty}\frac{(n+1)^2}{n+\frac{3}{2}} \bigg[\frac{\Gamma(n+1)}{\Gamma(n+\frac{3}{2})}\bigg]^2=1$$
2026-03-31 14:23:15.1774966995
Reduce to Wallis formula
316 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in LIMITS
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