Relating the coefficients of the characteristic polynomial of a symmetric matrix to the determinants of its principal submatrices

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I've been thinking about this this problem:

Let $M$ be a symmetric matrix. Recall that the eigenvalues of $M$ are the roots of the characteristic polynomial of M:

$p(x) := det(xI-M) = \prod\limits_{i=1}^n (x-\mu_i)$

Write

$p(x) = \sum\limits_{k=0}^n x^{n-k} c_k (-1)^k$

Prove that

$c_k = \sum\limits_{S \subseteq [n], |S|=k} \det(M(S,S)). $

Here, we write $[n]$ to denote the set $\{1, 2, \ldots, n\}$, and $M(S,S)$ to denote the submatrix of $M$ with rows and columns indexed by $S$.

I am a little confused on how to relate the coefficients back to the determinants of submatricies of $M$.

I think it's not too tricky using the product formulation for the characteristic polynomial that the coefficients $c_k$ are the sum of all k-wise products of eigenvalues. Each coefficient $c_k$ then corresponds to the sum of all determinants of principal submatrices of size $k$ for the matrix $\Lambda$ if you write $M = U\Lambda U^T$ via the spectral theorem. Since $U^T = U^{-1}$, $M$ is similar to $\Lambda$. Can you then say that since it is true for the diagonal matrix, it is true of the matrix itself because of similarity? I know the eigenvalues don't necessarily correspond to the respective submatrices of $M$ via Cauchy's interlacing theorem, so it's confusing to me how to jump back to talking about submatrices of $M$.

Or do you need to use some formulation of the determinant to show this?

Thanks in advance!

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The detour through the eigenvalues will not help. Using the notations of your link, recall that $[n]=\{1,\ldots,n\}$ and let $M(S,T)$ denote the matrix obtained from $M$ by only keeping the rows with index in $S$ and columns with index in $T$. The the first thing you need is $$ \frac{\partial}{\partial M_{ij}}{\rm det}(M)=(-1)^{i+j}\ {\rm det}(\ M(\ [n]\backslash\{i\},\ [n]\backslash\{j\}\ )\ ) $$ which follows from the expansion with respect to say the $j$-th column. Then, express the $c_k$'s as derivatives at zero of the characteristic polynomial. Finally, compute these derivatives using the multivariate chain rule and the formula above.