Suppose $\lambda_0$ be an eigenvalue of $A$ with algebraic multiplicity $k$; If $k>\dim Null(A-\lambda_0 I)$, then $A$ is not diagonalizable. is this statement true or false? could anyone help me to solve?
2026-04-03 20:11:18.1775247078
relation between algebraic multiplicity and diagonalization
86 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in EIGENVALUES-EIGENVECTORS
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