How is the property $b^{x+y} = b^x\cdot b^y$ related to the property $\log_b(xy) = \log_b(x)+\log_b(y)$?
2026-03-30 20:50:08.1774903808
Relationship between exponent and logarithm
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1
Very strongly.
Hint: Write $A:=b^x$ and $B:=b^y$.