Relative interior of convex set and its closure coincide in infinite dimensional spaces?

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Let $X$ be an infinite dimensional Banach space, and $C\subset X$ a convex set. Is it always true $\text{ri}(C)=\text{ri}\left(\overline{C}\right)$?

What about for general topological vector spaces? Thanks.

Background: I've been trying to seriously understand results about convex sets in functional analysis. Previously, I've always just take things like Krein-Milman for granted. So initially I'm trying to see whether we always have $\text{ri}(C)\neq \emptyset$. But there's a counterexample here. Then I guessed maybe that's true when $C$ is closed? Then, I can see the same counterexample still stands when taking the closure. Another counterexample for closed convex set is here. These counterexamples make me wonder whether the statement above is true.

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No. In an infinite-dimensional Banach space $X$, you can have a proper subspace $E$ that is dense. $E$ is convex, and $\text{ri}(E) = E$, but $\text{ri}(\overline{E}) = \overline{E} = X$.