Restriction of a Smooth chart is Again a Smooth Chart

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Let $M$ be a smooth manifold with $\mathscr A=\{(U_\alpha,\varphi_\alpha)\}_{\alpha\in J}$ being its smooth structure.

Let $V$ be open in $M$ and $(U,\varphi)\in \mathscr A$.

Define $\psi:U\cap V\to \varphi(U\cap V)$ as $\psi(p)=\varphi(p)$ for all $p\in V$.

We note that $(V\cap U,\psi)$ is a chart on $M$.

QUESTION: Does $(V\cap U,\psi)\in\mathscr A$?

I think the answer to the above question is yes because $(V\cap U,\psi)$ is smoothly compatible with every member of $\mathscr A$. Thus $(V\cap U,\psi)\in\mathscr A$.

Can somebody confirm that I am correct or else point out a mistake?

PS: I am an absolute beginner in Differential Geometry.

Thank you.