It should be easy calculation exercise in my text, but I am afraid I am a little bit stuck on the concept of the question.
Let $f:\Bbb R^n\to \Bbb R$ be a smooth function. Consider graph $X$ of $f$ in $\Bbb R^{n+1}$. It is $n$-dimensional smooth manifold with chart $(X,\Bbb R^n,\varphi)$ where $\varphi: \Bbb R^n\to X$ by $\varphi(x)=(x,f(x))$. If $\sigma$ is Riemannian volume form on $X$ prove that
$$\varphi^*\sigma=\sqrt{1+\sum_{k=1}^n{(\frac{\partial f}{\partial x_k})^2}}dx_1\wedge dx_2 \wedge ... \wedge dx_n.$$
If $g$ is the Riemannian metric on $X$ induced by the Euclidean metric in $\mathbb R^{n+1}$ then $dV_g(x)=f(x)dx_1\wedge\dots\wedge dx_n$ where $f(x)$ is the Euclidean measure of the parallelotope generated by $\phi_\ast\partial_{x_1},\dots,\phi_\ast\partial_{x_n}.$
Now you have just to take the Euclidean norm of the vector in $\mathbb R^{n+1}$ whose components are the minors of the $(n+1)\times n$-matrix $(\phi_\ast\partial_{x_1},\dots,\phi_\ast\partial_{x_n})$.