Roots of trigonometric equation $\sin((n+1)\theta) + 2\sin(n\theta) = 0,\;\;\theta\neq k\pi\,\,k\in\mathbb{Z}.$

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I am trying to find a closed formula for the roots of the following trigonometric equation, $$\sin((n+1)\theta) + 2\sin(n\theta) = 0,\;\;\theta\neq k\pi\,\,k\in\mathbb{Z},$$ where $n$ is a positive integer.

Can anyone give me a hint?