Given
- A closed population with an external news source
- There is a chance someone who has heard the rumor transmits it to someone who has not
- There is a chance someone who believes the rumor begins to doubt it and will stop spreading it
Let
- $P(t)$ - the number of people who believe the rumor
- $T$ - total population
- $r$ - Chance each day of any one person hearing the rumor from an external source
- $c$ - Probability of a person who knows the rumor telling a person they meet who does not know the rumor
- $s$ - The probability of any two people meeting
- $d$ - The proportion of rumor believers who come to doubt the rumor each day
Attempt
I have tried to model this with:
$$\frac{dp}{dt} = r\left[T - P(t) - \frac{P(t)}{d}\right] + csP(t)\left[T - P(t) - \frac{P(t)}{d}\right] - \frac{P(t)}{d}$$
with the idea being that $\frac{P(t)}{d}$ represents the number of people who have stopped believing the rumor so $T - P(t) - \frac{P(t)}{d}$ represents the number of people who have not heard the rumor.
Although this model seems appropriate when $t=0$, when $t$ is very large I would expect $\frac{dp}{dt}$ to be zero, as everyone has heard the rumor, but no longer believes it.
Question:
How can I improve the model so that $\frac{dp}{dt}$ is $0$ when $t$ is very large?
I'd rather consider a simpler model: $$\dot{P}=r(T-P)-dP+\beta(T-P)P.$$ Note that
Regarding your question: did you mean $P(t)=0$ as $t\rightarrow \infty$? Otherwise the question is not clear.