$S = \{ A \in M_{n}(\mathbb{R}) : 0 <\operatorname{rank}(A) = p < n \}$ is a graph of a $C^{1}$ function

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Consider $S = \{ A \in M_{n}(\mathbb{R}) : 0 < \operatorname{rank}(A) = p < n\}$, where p is a fixed integer.

Suppose that $n = 2$ and $p = 1$. Show that, locally, $S$ is the graph of a real $C^1$ function. Find the tangent plane of $S$ in $$A_{0} = \pmatrix{ 0 & 0\\ 0 & 1 }$$

I don't have an interesting idea to prove this, maybe use the rank theorem, but I don't know how can I use it. Someone can help me? Thank you in advance