Scalar action on a projective curve

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I have an homogeneous quartic in $(u,v,w)\:$: $Q(u,v,w)=u^4+au^2w^2+bw^4-v^2$

For $\lambda$ in the base field $K$, I wish to calculate: $\lambda^4Q(u,v,w)=Q(u',v',w')$.

I 'm not sure but I find $u'=\lambda u$, $v'=\lambda^2v$, $w'=\lambda w$.

Do you think it's correct ?

I thank you in advance...