Schwartz-Bruhat function on the adele ring which is its own Fourier dual

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I was interested in how

  • $1_{\hat{ℤₚ}} : ℚₚ ⭢ ℂ$ is Fourier dual to itself
  • $e^{-πx^2} : ℝ ⭢ ℝ$ is Fourier dual to itself
  • $e^{-2πz\overline{z}} : ℂ ⭢ ℂ$ is Fourier dual to itself.

One question I have is:

Is $1_{\hat{ℤ}} : ⭢ ℂ$ Fourier dual to itself?

I thought there would be an equation involving $1_{\hat{ℤ}},1_{\hat{ℤₚ}}$, and $e^{-πx^2}$, much like $Π νₚ(x) = ||x||$.

How does $\hat{ℤ} ⊗ ℚ$ relate to ℝ? If the Adeles are $\hat{ℤ} ⊗ ℚ$, then where does the factor of $ℝ$ come from?