So my question is quite simple:
If an operator (which corresponds to a sesquilinear form) is semi-bounded (from below) then the sesquilinear form is also semi-bounded (from below)?
I'm pretty sure that this is true, but I dont know the proof.
2026-03-25 01:21:41.1774401701
Semi-bounded operator implies semi-bounded sesquilinear form
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