I was given the below formula to solve: $$ \sum_{k=1}^{40}k^{2k} $$
I'm not sure how to approach the problem considering $k$ isn't a constant to obtain any values. Any hints would be appreciated.
I was given the below formula to solve: $$ \sum_{k=1}^{40}k^{2k} $$
I'm not sure how to approach the problem considering $k$ isn't a constant to obtain any values. Any hints would be appreciated.
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Alpha gives the value $\sum_{k=1}^{40} k^{2 k} = 14616284255801992521053722308218024414349383839\\254327530879300523619661334347511\\3624778023973581416780282619663230939835404121156$
I'm not sure I am any wiser for finding this. Maybe you are expected to implement a big integer routine that can provide this answer?