Let $(X,\mathcal{T}_X)$ be a topological space, where $X=\{x\}$ is a point space, and hence $\mathcal{T}_X=\{\emptyset,\{x\}\}$.
Is it true that any sheaf $\mathcal{F}$ on $(X,\mathcal{T}_X)$ is a skyscraper sheaf? It seems that it is so by definition.
I define a skyscraper sheaf $S_x$ on the point $x\in X$ to be a sheaf $S_x:\mathcal{O}(X)^{op}\to\mathcal{C}$ where $\mathcal{C}$ is any category with a terminal object $T$, such that where $S\in\text{Ob}(\mathcal{C})$:
$$S_x(U)=\begin{cases}S,& x\in U,\\ T,&\text{ otherwise }\end{cases}$$ and for $f:V\hookrightarrow U$ I have $S_x(f)=id$ when $x\in V$ and is the unique terminal morphism otherwise.
It seems then that what I suggest is immediately true, just wanted a sanity check.