Shouldn't this be the standard way to prove that if $p>1$ then $p^n \to +\infty$?

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Proposition: Let $p>1$. We have $$ \lim_{n\to +\infty} p^n = +\infty.$$

My professor proved this setting $p=1+\varepsilon$ for some $\varepsilon>0$ and then using Bernoulli's inequality and the comparison theorem. Apart from using the definition of divergence, is this the standard way? I guess my question sort of regards didactics. I'm asking because I feel like the following is more elementary:

$\{p^n\}$ is strictly increasing: $$p^{n+1}>p^n \iff \frac{p^{n+1}}{p^n} =p>1 $$ therefore if it doesn't diverge, it must approach $\alpha\in (1,+\infty)$. But then so does $\{p^{n+1}\}$, which implies $$\lim_{n\to\infty} \frac{p^{n+1}}{p^n}=p=\frac\alpha\alpha=1,$$ contradicting the assumption $p>1$.

I avoided using directly the ratio test as it seems to be more advanced, at least according to my book.