i tried this and i got
set n=2
set c= 2
set a + b = 1
$\log _a\left(n\right)\:\le \:c\:\cdot \:\log _b\left(n\right)$
$\log _a\left(n\right)\:\le \:\:\log _b\left(n^c\right)$
$\log _a\left(2\right)\:\le \:\:\log _b\left(4\right)$
$1\le4$
I'll be honest, I dont really know how to do this
You can simply use the change of base formula for logarithms: $$ \log_b(n)=\frac{\log_a(n)}{\log_a(b)}$$ and observe that $\log_a(b)$ is a positive constant if $a,b>1$.