given following equation:
$x^D \leq Ax^B \leq Dx^D$
i want to show that $B \approx D$
I split the inequality into two parts.
- $x^D \leq Ax^B$
- $Ax^B \leq Dx^D$
I'm not sure, from the first part I can see that D is bigger than B. but I can't prove it, I think it's simple, I'm not sure.