Show that AQ = x cos θ + y sin θ

Question

Here is proberly a easy trigonometry question that i can't figure out

In the diagram to the right, ABCD is a rectangle in which AB = x and BC = y. BP and CQ are drawn perpendicular to the interval AE, >which is inclined at an angle θ to AB.

Show that $$AQ = x cos θ + y sin θ$$ Thanks

Answer 1

Hint: Construct the perpendicular line from Point $C$ to the line $$BP$$