where F is a differentiable function of $x, y,z, t$ and $x, y, z$ differentiable functions of $t$, Show that $\frac{dF}{dt}=\frac{\partial F}{\partial t}+\nabla F\cdot \frac{d\vec{r}}{dt}$
We define $\vec{r}=x\hat{i}+y\hat{j}+z\hat{k}$ as the position vector
I would like you to give me some suggestions. It has been difficult for me to know where to start
I did this but I don't know if it's okay
$\frac{dF}{dt}=\frac{\partial F}{\partial x}\frac{dx}{dt}+\frac{\partial F}{\partial y}\frac{dy}{dt}+\frac{\partial F}{\partial z}\frac{dz}{dt}+\frac{\partial F}{\partial t}\frac{dt}{dt}$
$\frac{dF}{dt}=(\frac{\partial F}{\partial x}\hat{i}+\frac{\partial F}{\partial y}\hat{j}+\frac{\partial F}{\partial z}\hat{k})\cdot(\frac{dx}{dt}\hat{i}+\frac{dy}{dt}\hat{j}+\frac{dz}{dt}\hat{k})+\frac{\partial F}{\partial t}$
$\frac{dF}{dt}=\nabla F\cdot \frac{d\vec{r}}{dt}+\frac{\partial F}{\partial t}$
Use the chain rule to get, $$\dfrac{dF}{dt}=\dfrac{\partial F}{\partial t}+\dfrac{\partial F}{\partial x}\dfrac{dx}{dt}+\dfrac{\partial F}{\partial y}\dfrac{dy}{dt}+\dfrac{\partial F}{\partial z}\dfrac{dz}{dt}$$
Should be clear from there.