Show that $\frac{|\sin x|}{x}$ is uniformly continuous on (0,1) and (-1,0) but not the union of both intervals

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Show that the function $\frac{|\sin x|}{x}$ is uniformly continuous on each of the intervals $I_1$ = (−1,0) and $I_2$ = (0,1). However show that this function f is not uniformly continuous on $I_1 ∪ I_2$.

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Hint:              

uniform continuity with as discontinuity