Show that $ \lim_{x\rightarrow\infty}\frac{2^{\sqrt{\log(x)}}}{\sqrt{x}} = 0 $

Question

I am trying to prove that $$ \lim_{x\rightarrow\infty}\frac{2^{\sqrt{\log(x)}}}{\sqrt{x}} = 0 $$

However, derivatives for using L'Hopital look really horrific. How can I prove the result?