Show that $\neg$ and $\wedge$ form a functionally complete collection of logical operators
Can someone give a hint?
2026-04-17 14:05:56.1776434756
Show that $\neg$ and $\wedge$ form a functionally complete collection of logical operators
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Hint. $p \vee q$ is equivalent to $\neg (\neg p \wedge \neg q)$ and $p \to q$ is equivalent to $q \vee \neg p$.