I have the following problem to resolve:
If $X=\{1,2,3,4,5\}$ and $V$ is the set of all the subsets of 2 elements of $X$. If $A$ is the set of pairs of elements of $V$ that are disjoint (as subsets of $X$). Show that the graph $G=(V,A)$ is isomorphic to the graph shown below:
From this, we know that:
$$X=\{1,2,3,4,5\}$$
And from what I understand:
$$ V=\{\{1,2\},\{1,3\},\{1,4\},\{1,5\},\{2,1\}\{...\}\} $$
But this seems incorrect as since $X$ appears to be representing the nodes of the graph, that set of subsets above would be $A$ and here is where I start getting confused.
Any suggestions on better understanding the concept of the problem and at the same time the steps in resolving it?


This is the Petersen graph. The set of vertices are the two element subsets of $\{1,2,3,4,5\}$ and two vertices are adjacent iff they are disjoint as sets. For example there is an edge between $\{1,2\}$ and $\{3,4\}$ (since $\{1,2\}\cap \{3,4\}=\varnothing$ but not an edge between $\{1,2\}$ and $\{2,3\}$ (since $\{1,2\}\cap \{2,3\}\neq\varnothing$). This graph has $\binom{5}{2}=10$ vertices.