The operator is defined as followed: $\hat A = a|u_{1}\rangle\langle u_{1}| + b|u_{2}\rangle\langle u_{2}|$
$a)\qquad a = b = 1$
$b)\qquad a = i, b = -i$
The operator is defined as followed: $\hat A = a|u_{1}\rangle\langle u_{1}| + b|u_{2}\rangle\langle u_{2}|$
$a)\qquad a = b = 1$
$b)\qquad a = i, b = -i$
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taking adjoint of $\ a|x\rangle\langle y|\ $ gives $\ a^*|y\rangle\langle x|\ $. And their adjoint of a sum (of ket-bra) is the sum of the adjoints