Showing a hyperbola in polar form approaches two asymptotes

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Consider a curve given in polar coordinates by $r(θ)=\frac{1}{1+e\cos\theta}$, where $e≥0$.

When $e>1$, show that the curve approaches two asymptotes, find them and sketch the curve. Hint: If the critical angles are $\pm\theta_0$, compute the vertical distance of the point of the curve at angle $\theta=θ_0+h$ to the line $θ=θ_0$, and take a limit using Taylor approximations.


Not really sure where to begin, I could get $y=\frac{\sin(\theta_0+h)}{1+e\cos(\theta_0+h)}$ and $y=(\tan\theta_0)x$ and then distance is $$\frac{\sin(\theta_0+h)}{1+e\cos(\theta_0+h)}-(\tan\theta_0)x$$

is this where I'm supposed to take limits?