Showing $\lim_{n \to \infty} \int |f_n| - |f - f_n| = \int |f|$

Question

I'm trying to show the following without using the Dominated Convergence Theorem:

Let $E \subseteq \mathbb{R}^d$ measurable, and $\{f_n\}$ a sequence of integrable functions on $E$. Assume that $\sup \int_E |f_n| < \infty$ and $f_n \to f$ pointwise a.e. Show that

$$\lim_{n \to \infty} \int_E \left(|f_n| - |f - f_n|\right) = \int_E |f|.$$

So far I have that:

Since $f_n \to f$ pointwise a.e. we have

$$ \begin{align} \int_E |f| &= \int_E \liminf_{n \to \infty}\left(|f_n| - |f - f_n|\right) \\ &\leq \liminf_{n \to \infty} \int_E (|f_n| - |f - f_n|) \tag{By Fatou's Theorem} \\ &= \int_E |f_n| - \limsup_{n \to \infty} \int_E |f - f_n|. \end{align}$$

I suppose I now need to show $\int_E |f| \geq \int_E |f_n| - \limsup_{n \to \infty} \int_E |f - f_n|$, but I am unsure how to proceed. Also, it's clear that $f$ is in $L^{1}(E)$ space, but I'm unsure if/how that is helpful either.

Answer 1

$||f_n|-|f_n-f|| \leq |f|$ so DCT can be applied.