Hello I have to show that this improper integral is convergent: $$\int_{0}^{1} \frac{e^{\frac{-1}{x}}}{x^2} dx$$ , but I don't have any starting ideea. Any tips would be great, thank you.
2026-04-03 04:23:45.1775190225
Showing the convergence of improper integral.
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try change of variables, $y = \frac 1 x $ the integral reduces to $$\int_{\infty}^1 -e^{-y} dy $$