"Simple" ordered fields proof: show that $0<y^{-1}<1$

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Given that $x>0$ and $y=x+1$ show that $0<y^{-1}<1$ specifying what proprieties of the Ordered Field you are using.

I really struggle to understand whether I have demonstrated the theorem properly or not.

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Hint. Use the following facts:

  • (Adding inequalities) $a\le b$ and $c\le d$ implies $a+c\le b+d$,
  • If $0<a<b$, then $0<\frac1b<\frac1a$.