Two people working together can do a job in 3 hrs. How long will it take the slower person to do the same job if one of them is 3 times as fast as the other?
A) 1 hr
B) 1.5 hr
C) 1/3
D) 4 hr
$$WORK$$ Together 1 job in 3 hours = $\frac{1}{3}$
X = Time
Slower Person = $\frac{1}{3x}$
Faster Person = $\frac{1}{x}$
$$Equation$$ $$\frac{1}{x}+\frac{1}{3x}=\frac{1}{3}$$ After solving x=4 (it takes 4 hrs for the fastest person to do 1 job )
To find the slowest person we plug x into $\frac{1}{3x}$
We get 12 hours for the slowest person to do 1 job.
The problem is that 12 hrs is not in the answers, Did I did something wrong?
Your explanation is hard to follow, but the slower person taking $12$ hours and the faster taking $4$ hours is correct. Clearly the intended answer is $4$ hours as that is the only choice longer than $3$ hours and having only one person work must take longer. Probably the slower in the question is a misprint for faster, when $4$ hours would be correct.