Simplification - Boolean Algebra using DeMorgan law

Question

Can somebody please help me simplify this expression using DeMorgan law.

$\lnot{(A\land B)}+\lnot{(\lnot{A}\land B)}$

Thank you.

Answer 1

Present for the day:

$\overline{AB}+\overline{{\bar A}B} = \bar{A} + \bar{B} + A + \bar{B} = A + \bar{A} +\bar{B}= 1+\bar{B} = 1$