Simplification of $n^{1/\sqrt{\log n}}$

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I would like to simplify this function, how can we do it ?

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You may write, for $n >1$,

$$ n^{1/\sqrt{\log n}}=e^{\log n/\sqrt{\log n}}=e^{\sqrt{\log n}} $$

using $$ a^b=e^{b \log a}, \qquad a>0, \,b>0. $$

0
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$$n=e^{\log n}$$

$$n^{1/(\log n)^{1/2}} =e^{(\log n)^{1/2}}$$