Simplification of vectors

Question

Can the expression $(5\vec{u} \times \vec{v})\cdot(2 \vec{u}-7\vec{v})$ be simplified? $\vec{v}$ and $\vec{u}$ are not necessarily part of any orthogonal system. I don't really know how to use any kind of distributive property to go any further... The "$\cdot$" is dot product and "$\times$" is cross product. Isn't this just equal to $0$??

Answer 1

$(\vec x \times \vec y)\cdot \vec x=0$, for any vectors $\vec x$ and $\vec y$, because the cross-product of $\vec x$ and $\vec y$ is perpendicular to $\vec x$. Now distribute the $(5\vec u\times\vec v)$.

Answer 2

If given no knowledge of what $\vec{u}$ and $\vec{v}$ are equal to, then $$(5\vec{u} \times \vec{v})\cdot(2 \vec{u}-7\vec{v}) $$ is already simplified as far as possible.