The question I have been given is to simplify as much as possible: $\frac{\sqrt {24}}{8}$. I know the answer is $\frac{\sqrt 6}{4}$
(Note I am in a beginner math course, so go easy on me.)
My first thought was to divide to get: $\frac{\sqrt {12}}{4}$ and then again: $\frac{\sqrt 3}{1}$. However, I realized this was wrong. So I tried $\frac{\sqrt {24}}{2\times\sqrt 4}$ which would make the denominator equal to 4, which is right. So I thought I could do that to the top too, but I couldn't. I feel like I'm on the right track but not really there. Can someone help me figure out how to solve questions like these?
You should first simplify the square root part as much as possible, then cancel the fraction.
$$\sqrt{24}=\sqrt{4\times 6}=\sqrt{4}\times\sqrt{6}=2\sqrt{6}$$
Here you should always be trying to make one of the factors the largest square number that divides the number you are taking the square root of (here $4$ is the largest square that divides $24$).
Now you can simplify the fraction: $$\frac{\sqrt{24}}{8}=\frac{2\times\sqrt{6}}{8}=\frac{1\times\sqrt{6}}4=\frac{\sqrt{6}}4.$$
when doing this you can only cancel numbers from the top and bottom if they are both outside the square root (or both inside).