simplify fraction with parentheses

Question

$(3/2 - 7/10)$ / $2/3 + 1/10$

In this case $( )$ should be done first right

so $4/5$ / $2/3 + 1/10$

now because of order of operations it should be $4/5 * 3/2$ and then $ + 1/10$ right ?

At the end I get $13/10$ and because 13 is a prime number you cant simplify it anymore

but according to symbolab it should be $24/23$

copy this \frac{\left(\frac{3}{2}-\frac{7}{10}\right)}{\frac{2}{3}+\frac{1}{10}}

Is this not the same ? or does it change because $/$ is for only $(3/2 - 7/10)$ / $2/3$ If it is like that then I am dumb as**** for confusing it

Answer 1

$$\frac{\left(\frac{3}{2}-\frac{7}{10}\right)}{\frac{2}{3}+\frac{1}{10}}$$

I just copied your code.

You were evaluating: $$\frac{\left(\frac{3}{2}-\frac{7}{10}\right)}{\frac{2}{3}}+\frac{1}{10}$$

with the code: \frac{\left(\frac{3}{2}-\frac{7}{10}\right)}{\frac{2}{3}}+\frac{1}{10}

Answer 2

The problem its easy to solve. First of all, your code its not the same what you want, the correct code is \dfrac{\frac{3}{2}-\frac{7}{10}}{\frac{2}{3}}+\frac{1}{10}. After that,

$$\dfrac{\frac{3}{2}-\frac{7}{10}}{\frac{2}{3}}+\frac{1}{10}=\dfrac{\frac{4}{5}}{\frac{2}{3}}+\frac{1}{10}=$$ $$\frac{12}{10}+\frac{1}{10}=\frac{13}{10}$$