I am trying to simplify this natural log expression the best that I can, but I am unsure what to do in order to separate $b(x-t)$. Would it be $\log(b) + \log (x/t)$? so would the whole thing be:
$$ \log (\alpha + b) + \log (x/t) + \log k \quad?$$
Thank you!
No. You can't separate $log(A+B)$ into two logarithms, no matter what $A$ and $B$ are. The only things you can separate are $\log(AB)=\log(A)+\log(B)$, $\log_B(A)=\frac{\log(A)}{\log(B)}$ and $\log(A^B)=B\log(A)$, and their inverse operations