Simplify: $S=3^{1/3}\cdot 7^{1/4}$

92 Views Asked by At

Simplify: $$S=3^{1/3}\cdot7^{1/4}$$

How is it possible to simplify this? The exponents are completely different.

2

There are 2 best solutions below

1
On

it is impossible to simplify this (you wrote the reason).

only you can write this as $\sqrt[12]{3^4\cdot 7^3}$

2
On

$3=7×(3/7)$ therfore $3^{1/3}=(3/7)^{1/3}*7^{1/3} $ therfore $3^{1/3}*7^{1/4} =(3/7)^{1/3}*7^{1/3} *7^{1/4} = (3/7)^{1/3}*7^{7/12} $

the final term still has two bases to two exponents but I find it a simplified form to work with. Simplification to one term to a power is impossible due to 3 and 7 are coprime. In fact they are simply prime.