Simplify the following expressions in (1) sum of products and (2) products of sum :

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a) x'z' + y'z'+ yz' + xy

b) (A'+B'+D')(A+B'+C')(A'+B+D')(B+C'+D')

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Assuming that you are using the notation in a boolean algebra it appears you could simplify this by grouping or expanding:

a) $x'z'+y'z'+yz'+xy = (x'+y'+y)z' +xy $

b) $(A'+B'+D')(A+B'+C')(A'+B+D')(B+C'+D')=(A'+B'+D')(A'+B+D')(A+B'+C')(B+C'+D')=(A'+D')(A+B'+C')(B+C'+D')$

I'll leave the rest for you to reason about.